god og effektiv rute til selvsyntetisering af 2b4m (gennemsnitlig 50 usd pr. kg)

Dr. MMX

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Hej, jeg vil bare skrive reagenser brugt af wise choice (pris/indsats), der kan købes i Europa
så 1.
PCL5 med elementært svovl > thionylchlorid

thionylchlorid + propionsyre > priopionyklchlorid

4mp-syntese (her er et emne, så jeg vil bare linke):
Propionylchlorid
Toluen
AlCl3 vandfri

http://bbzzzsvqcrqtki6umym6itiixfhni37ybtt7mkbjyxn2pgllzxf2qgyd.onion/en/threads/synthesis-of-4-methylpropiophenone-from-toluene-by-friedel-crafts-reaction-1kg-scale.209/


nogle kan have problemer med at brominere det
svovlsyre, der er nødvendig for at få Hbr, der er lidt dyrt og ikke ofte tilgængeligt. I stedet bruger vi:
fosforsyre og NaBh til reaktoin> vi får HBR
H2O2 12% kan købes og destilleres til nogle flere % som 25-30%.


4 methylpropion + HBR + h2o2 > 2b4m :)

jeg har ikke beregnet omkostningerne, men de er meget små, og der er ingen grund til at vente på forsendelse eller blive overrasket over en forløber af lav kvalitet.
 
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chost

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Kan du forklare mere detaljeret, hvordan man laver HBR?
 

Dr. MMX

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Åh, jeg er virkelig ked af, at jeg lavede en fejl. Det er korrekt:
For at producere brintoverilte (HBr) fra fosforsyre (H₃PO₄) og natriumbromid (NaBr) kan du bruge en dobbeltfortrængningsreaktion. Reaktionen kan repræsenteres som følger:


  1. Reaktanter: Fosforsyre (H₃PO₄) og natriumbromid (NaBr).
  2. Produkter: Brintoverilte (HBr) og natriumfosfat (Na₃PO₄).

Den afbalancerede kemiske ligning for reaktionen er:


H3PO4+3NaBr→3HBr+Na3PO4


I denne reaktion reagerer fosforsyre med natriumbromid for at producere brintoverilte og natriumfosfat.
 
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chost

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Er destillation nødvendig?
Og i hvor meget vand skal jeg opløse natriumbromid?
 

Dr. MMX

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Hvordan har du ellers tænkt dig at få noget, der grundlæggende er en gas? :)

Det afhænger af, hvilken procentdel du vil have, max er 47%, som jeg husker det, og det burde allerede være på denne måde
 

Benz88

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is it Safe to Distille the h2o2 to maybe 30-35% from 12%?
 

Dr. MMX

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TheVacuumGuy

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H3po4 med NaBr for at producere HBr? Jeg vil prøve dette om et øjeblik.

Jeg har masser af HBr, men er bare nysgerrig efter, om de to reagerer.
 

Dr. MMX

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ja og Na3PO4
 

Dr. MMX

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Det er vidunderligt
 
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TheVacuumGuy

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Didn't work. I think it would be easier to add sulfuric acid to a solution of KBr (or NaBr) , which would readily yield HBr at 125c
 

Dr. MMX

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I tried to override having sulfuric acid becasue here is troubles to get it. It was very extreme attempt
if there is access to sulfuric acid its easy job
 

Dr. MMX

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you can get elemental bromine from potasium bromide, dont need to use acids.
it was quite cheap as i remember
 

Toddler

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Hbr2 48% can work ?
(CAS.No: 10035-10-6)

how much ration use for bromination
Hbr2
H2O2
for 100g of 4MPP
 
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w2x3f5

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Instead of propionyl chloride, can use propionic anhydride (obtain phosphorus oxide from propionic acid), can also use propionic acid directly with polyphosphoric acid (there are many options for this reaction, you can choose the best one). If propionyl chloride is used with anhydrous aluminum chloride (can be replaced with cheaper and simpler options). Then it is best to carry out a bromination reaction before hydrolysis in Fridel-Crafts (the complex of 2b4m and aluminum chloride is very active for bromination with a high yield).
 

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In chemistry trade buissness in europe propionic acid is considered with "silent restriction" with reason it can be used as biological weapon, so should be avoided there.

very interesting choice of propionic anhydride
 

Osmosis Vanderwaal

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@TheVacuumGuy you gave him bad figures and he used them and probably ruined 100G 2B4-MP. I dont know what he paid, but I got $200 all day for 10g if it's domestic . In th rules there are a few gold nuggets. "Use the fucking search engine." That's a rule. Another one is " a good chemist i an accurate chemist." Make sure that you clearly state you are guessing when you don't know. You could say nothing at all, you could show your math or you could tell him he needs to figure it himself, but please, dont just throw out random numbers, with no disclaimer.
 
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